SOLUTION: https://gyazo.com/9fa27dadbd0ad63a30e8ff0166320983

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Question 1177787: https://gyazo.com/9fa27dadbd0ad63a30e8ff0166320983
Found 2 solutions by MathLover1, greenestamps:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

the area original uncut box is 51cm by 45cm
you deduct 2x from the length and from the width
then the volume will be
V=x%2851-2x%29%2845-2x%29
given that V=7175cm%5E2
7175=x%2851-2x%29%2845-2x%29...expand and solve for x
4x%5E3+-+192x%5E2+%2B+2295x+-+7175+=+0 ......using calculator, we get
x=5
then dimensions of the box are
51-2x=51-10=41-> length
45-2x=45-10=35->width
x->height
check:
7175=x%2851-2x%29%2845-2x%29+
7175=5%2841%29%2835%29+
7175=7175


Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


The question asks for a formal algebraic solution; the response from the other tutor shows a typical good one.

Note that, if formal algebra were not required, and if the speed of getting an answer were important (as in a timed math competition), then logical reasoning and some mental arithmetic can get you to the answer very quickly.

The volume is to be 7175; so find the prime factorization of 7175 and use that and logical reasoning to find the answer to the problem.

7175 = 5*1435 = 5*5*287 = 5*5*7*41

The dimensions of the original piece of cardboard differ by 6; and 5*7=35 is 6 less than 41. So the dimensions of the box are 5x35x41