SOLUTION: 1/i^57 how do you work on this problem to get the answer. It is one over i with the square root of 57

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Question 1175431: 1/i^57 how do you work on this problem to get the answer. It is one over i with the square root of 57
Found 3 solutions by ewatrrr, greenestamps, Alan3354:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi
IF +1%2F%28i%2Asqrt%2857%29%29
The task it appears is to rationalize the denominator 
by Multiplying both numerator and denominator by i√57 
Note: i^2 = -1
 +1%2F%28i%2Asqrt%2857%29%29=+i%2Asqrt%2857%29%2F%28-57%29=+-i%2Asqrt%2857%29%2F%2857%29+
Wish You the Best in your Studies.


Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


I don't know how the other tutor got a square root into this problem....

The given expression is

1%2Fi%5E57

In mostly all applications, we don't want to leave an imaginary number in the denominator. We want to rationalize the denominator by multiplying by some power of i to make the denominator a real number.

i^(4n) is equal to 1 for all integers n. So rationalize the expression by multiplying numerator and denominator by i^3, so that the exponent in the denominator is a multiple of 4.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
1/i^57 how do you work on this problem to get the answer. It is one over i with the square root of 57
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1/i^57 is not a problem.
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