SOLUTION: b+3+10=6(9b-8)-10(6b+10)

Algebra ->  Equations -> SOLUTION: b+3+10=6(9b-8)-10(6b+10)      Log On


   



Question 117493: b+3+10=6(9b-8)-10(6b+10)
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

b%2B3%2B10=6%289b-8%29-10%286b%2B10%29 Start with the given equation



b%2B3%2B10=54b-48-60b-100 Distribute


b%2B13=54b-48-60b-100 Combine like terms on the left side


b%2B13=-6b-148 Combine like terms on the right side


b=-6b-148-13Subtract 13 from both sides


b%2B6b=-148-13 Add 6b to both sides


7b=-148-13 Combine like terms on the left side


7b=-161 Combine like terms on the right side


b=%28-161%29%2F%287%29 Divide both sides by 7 to isolate b



b=-23 Divide

--------------------------------------------------------------
Answer:
So our answer is b=-23