SOLUTION: A stone is dropped into a mine shaft and hits the bottom 4.25 s later. How deep is the mine shaft? The equation for the distance an object falls in T seconds is T =sqrt(d/16), wher

Question 1174319: A stone is dropped into a mine shaft and hits the bottom 4.25 s later. How deep is the mine shaft? The equation for the distance an object falls in T seconds is T =sqrt(d/16), where d is the distance in feet.
Answer by ikleyn(52788) (Show Source): You can put this solution on YOUR website!
.


From the condition, you write this equation


    4.25 = 


Then you square both sides


    4.25^2 = d/16


and finally obtain  d = 16*4.25^2 = 289 ft.    ANSWER

Solved.

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