SOLUTION: Hello out there,I need some help with some tough problems,the first one is,Simplify:15/30.The next one is,Simplify:9/k+8/k.The third one is,Simplify:8t/21-5t/21.And the last one is
Algebra ->
Equations
-> SOLUTION: Hello out there,I need some help with some tough problems,the first one is,Simplify:15/30.The next one is,Simplify:9/k+8/k.The third one is,Simplify:8t/21-5t/21.And the last one is
Log On
Question 117353: Hello out there,I need some help with some tough problems,the first one is,Simplify:15/30.The next one is,Simplify:9/k+8/k.The third one is,Simplify:8t/21-5t/21.And the last one is,Simplify:p/8+3p/8,thanks to whoever can help. Answer by jim_thompson5910(35256) (Show Source):
In order to reduce , the numerator and denominator must share a common factor. This common number must evenly divide into both of them without any remainder or decimal.
In order to completely reduce the fraction, you must divide the numerator and the denominator by the greatest common factor (GCF). The GCF of and is (note: click here if you need help with finding the GCF). So divide both the numerator and denominator by
In other words, to reduce the fraction you do this
Plug in the numerator, denominator, and the GCF
Now divide 15 by to get 1. This is now the new numerator.
Now divide 30 by to get 2. This is now the new denominator.
So
This means that reduces to
In other words,
"Simplify:9/k+8/k"
Start with the given expression
Since the denominators are all equal, we can combine the numerators
Now combine like terms
So
#3
"8t/21-5t/21"
Start with the given expression
Since the denominators are all equal, we can combine the numerators
So
#4
"Simplify:p/8+3p/8"
Start with the given expression
Since the denominators are all equal, we can combine the numerators