After distributing, the above asks:
If 12x+15š=P, in terms of P what is the value of 36x+60š?
Let k and m be such that:
36x + 60š = kP + mš
36x + 60š = k(12x+15š) + mš
36x + 60š = 12kx + 15kš + mš
We set coefficients of x equal:
36 = 12k
3 = k
We set constants equal
60š = 15kš + mš
60 = 15k + m
60 = 15(3) + m
60 = 45 + m
15 = m
so
36x + 60š = kP + mš = 3P + 15š
or
6(6x+10š) = 3P + 15š <--answer
Edwin
We are given = P.
It is the same as = P. (1)
Then = 36x + = regroup = 36x + + = + =
Now I replace by P, based on (1), and continue the chain of equalities in this way
= . Completed.
ANSWER. Then = .
Solved.
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In short terms, I did THIS:
From the expression, which is under the question, I extracted the part, proportional to the given expression.
Then I replaced this extracted part by the given value (symbol P, in this case). The remaining addend was simply some constant.
That's all. It is small trick :), actually - - - to learn for beginners.