Question 1172312: The equation of catenary is given by the following second order differential equation:
(5 Marks)
y"=5
x = 0, y = 100.2
x =100.1, y =100.1
Solve the above differential equation and plot the curve at 10m intervals
Answer by ikleyn(52781)   (Show Source):
You can put this solution on YOUR website! .
The general solution to the given differential equation is
y(x) = 2.5x^2 + bx + c,
where b and c are unknown constant values.
To find these unknown values, use the given boundary conditions
a) at x= 0 2.5*0^2 + b*0 + c = 100.2, which gives c = 100.2;
b) at x= 100.1: 2.5*100.1^2 + b*100.1 + 100.2 = 100.1 which gives
25150.225 + 100.2b = 100.1
100.2b = 100.1 - 25150.225 = -25050.125
b = -25050.125/100.2 = -250.0012475.
It gives your solution/answer.
Solved, explained, answered and completed.
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