SOLUTION: 3. What is the value of k that will make the trinomial 64x2 + 56x + k be a perfect square? Show clear solution thanksss!

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Question 1172154: 3. What is the value of k that will make the trinomial 64x2 + 56x + k be a perfect square? Show clear solution thanksss!
Found 3 solutions by ikleyn, math_tutor2020, MathTherapy:
Answer by ikleyn(52780) About Me  (Show Source):
Answer by math_tutor2020(3816) About Me  (Show Source):
You can put this solution on YOUR website!

Consider the perfect square trinomial formula
(a+b)^2 = a^2 + 2ab + b^2

The expression 64x^2+56x+k has three terms, as does the right hand side of the equation above.

Equating the two expressions shows that
64x^2 = a^2
56x = 2ab
k = b^2

To find k, we'll need to figure out b.
To figure out b, we need to find 'a' first

If 64x^2 = a^2, then
a^2 = 64x^2
a^2 = (8x)^2
a = 8x
where the last step has us apply the square root to both sides.
We could end up with a = -8x, but this value will ultimately lead to the same value of k. So we'll stick to a = 8x to make things simple.

Use that value of 'a', and the second equation we formed, to get
56x = 2ab
56x = 2(8x)b
56x = 16xb
56 = 16b
16b = 56
b = 56/16
b = (8*7)/(8*2)
b = 7/2
Note: if you went with a = -8x, then b = -7/2. Otherwise, b is positive.

Now we can compute k
k = b^2
k = (7/2)^2
k = (7^2)/(2^2)
k = 49/4

This means 64x^2+56x+k updates to 64x%5E2%2B56x%2B49%2F4 which factors to %288x%2B7%2F2%29%5E2.
Use the perfect square trinomial formula template, given at the very top of the solution, to help factor.
Because we can rewrite 64x%5E2%2B56x%2B49%2F4 into the form (expression)^2, this proves 64x%5E2%2B56x%2B49%2F4 is a perfect square trinomial.

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Answer: 49/4
In decimal form, this is exactly 49/4 = 12.25


Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
3. What is the value of k that will make the trinomial 64x2 + 56x + k be a perfect square? Show clear solution thanksss!
You just need to COMPLETE the SQUARE, as follows: 
Therefore, as seen above,