You can put this solution on YOUR website! x^2+3x+sqrt{x^2+3x}=6. Find x.
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It's on the far left. JK
I would say "Solve for x, tho."
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You can do a lot of algebra, but first consider that sqrt(x^2+3x) is likely to be an integer. So x^2+3x is a perfect square.
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x = 1 fits.
There might be other solutions.
You can put this solution on YOUR website! let x^2+3x=w^2
so w^2+w-6=0
(w+3)(w-2)=0
w=-3, w=2, but w=-3 is extraneous, as sqrt (x^2+3x) cannot be negative.
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(x^2+3x-4=0
(x+4)(x-1)=0
x=-4, 1
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