SOLUTION: The sum of the ages of two sisters, Mary and Jane, is 24 years. Four years ago three times Mary’s age was 3 years more than twice Jane’s age. Determine their current ages

Algebra ->  Equations -> SOLUTION: The sum of the ages of two sisters, Mary and Jane, is 24 years. Four years ago three times Mary’s age was 3 years more than twice Jane’s age. Determine their current ages      Log On


   

Question 1170351: The sum of the ages of two sisters, Mary and Jane, is 24 years. Four years ago three
times Mary’s age was 3 years more than twice Jane’s age. Determine their current ages
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
m Mary, 11
j Jane, 13


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3%28m-4%29=3%2B2%28j-4%29
3m-12=3%2B2j-8
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3m=7%2B48-2m
5m=55
highlight%28m=11%29