SOLUTION: 1.a) Deduce that the total surface area S of a cylinder closed at both ends with height, H and base radius R is given by: S=2πR(R+H) where π is a constant. b) Find the volume of

Algebra ->  Equations -> SOLUTION: 1.a) Deduce that the total surface area S of a cylinder closed at both ends with height, H and base radius R is given by: S=2πR(R+H) where π is a constant. b) Find the volume of      Log On


   



Question 1170246: 1.a) Deduce that the total surface area S of a cylinder closed at both ends with height, H and base radius R is given by: S=2πR(R+H) where π is a constant.
b) Find the volume of S given that H =15.0m and R =5.0m (leaving your answer in terms of π)
c) Calculate the amount of water the tank can hold leaving your answer in terms of π.
d) Calculate the height (h) of a cuboid tank of cross-sectional area 25 metre cube which has the same capacity as the cylinder tank in (c) above.


Found 2 solutions by mananth, ikleyn:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
1.a) Deduce that the total surface area S of a cylinder closed at both ends with height, H and base radius R is given by: S=2πR(R+H) where π is a constant.
The total surface area comprises of the circular bases at top and bottom and the lateral surface area
Area of bases = 2 pi r^2
Lateral surface area = circumference * height = 2 pi r
Total surface area = 2pi r^2+2pirh = 2pir(r+h)
b) Find the volume of S given that H =15.0m and R =5.0m (leaving your answer in terms of π)
S = 2*pi*5(15+5)= 200 pi m^3

c) Calculate the amount of water the tank can hold leaving your answer in terms of π.
1m^3= 1000 litres
d) Calculate the height (h) of a cuboid tank of cross-sectional area 25 metre cube which has the same capacity as the cylinder tank in (c) above.
V = area * height
200pi= 25*h
h=8pi

Answer by ikleyn(52777) About Me  (Show Source):
You can put this solution on YOUR website!
.
1.a) Deduce that the total surface area S of a cylinder closed at both ends with height,
H and base radius R is given by: S=2πR(R+H) where π is a constant.
b) Find the volume of S given that H =15.0m and R =5.0m (leaving your answer in terms of π)
c) Calculate the amount of water the tank can hold leaving your answer in terms of π.
d) Calculate the height (h) of a cuboid tank of cross-sectional area 25 metre cube
which has the same capacity as the cylinder tank in (c) above.
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How your problem is printed and presented in this post - it is a  MESS,
impermissible in  Math.

Thus,  in part  b)  you write  " Find the volume of S ",  but letter S is just employed
in part  a),  where it denotes the surface area.   You can not use it for the volume.

In part  d)  you write  " cross sectional area  25  metre cube",
but cross sectional area is  NEVER  measured in meters cube:  the adequate measure unit is meter square.


        Writing  Math problem is not the same as celling vegetable and fruits
        at the farmer's market.   It requires accurate using of words.


All calculations in the post by @mananth in parts  b),  c)  and  d)  are   highlight%28highlight%28FATALLY%29%29   highlight%28highlight%28wrong%29%29.

If you want to get accurate answer/solution,  you should print/present your post/problem accurately.


        Revise your post,  fix your errors,  then re-post.


Do you re-write your problems from a source (like textbook),
or translate them from other language, or get them by phone, or create on your own ?


If you copy-paste it from some Internet site/file, then it means that this source is DEFECTIVE.


        In whole, the creator of this post deserves a ticket
        and a penalty for his (or her) unsatisfactory job.