SOLUTION: solve for 'x' b^2x^2+a^2y^2=a^2b^2

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Question 116976: solve for 'x'
b^2x^2+a^2y^2=a^2b^2

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

b%5E2x%5E2%2Ba%5E2y%5E2=a%5E2b%5E2 Start with the given equation



b%5E2x%5E2=a%5E2b%5E2-a%5E2y%5E2Subtract a^2y^2 from both sides


x%5E2=%28a%5E2b%5E2-a%5E2y%5E2%29%2Fb%5E2 Divide both sides by b%5E2


x=sqrt%28%28a%5E2b%5E2-a%5E2y%5E2%29%2Fb%5E2%29 Take the square root of both sides



x=sqrt%28%28a%5E2b%5E2-a%5E2y%5E2%29%29%2Fb Simplify



x=sqrt%28a%5E2%28b%5E2-y%5E2%29%29%2Fb Factor out a%5E2



x=a%2Asqrt%28b%5E2-y%5E2%29%2Fb Simplify