SOLUTION: Have I simplified the problem correctly? 3x^2 + 6x -45 divided by 3x^2 +21x+30 = I come up with answer of 3(x=5)(x-3) over 3x^2 +21X + 30 Thank you

Algebra ->  Equations -> SOLUTION: Have I simplified the problem correctly? 3x^2 + 6x -45 divided by 3x^2 +21x+30 = I come up with answer of 3(x=5)(x-3) over 3x^2 +21X + 30 Thank you       Log On


   

Question 1169451: Have I simplified the problem correctly?
3x^2 + 6x -45 divided by 3x^2 +21x+30 =
I come up with answer of 3(x=5)(x-3) over 3x^2 +21X + 30
Thank you

Found 2 solutions by htmentor, MathTherapy:
Answer by htmentor(1343) About Me  (Show Source):
You can put this solution on YOUR website!
(3x^2+6x-45)/(3x^2+21x+30) -> 3(x^2+2x-15)/(3(x^2+7x+10)
The 3's cancel and we can factor the numerator and denominator as follows:
(x+5)(x-3)/((x+5)(x+2)) -> (x-3)/(x+2)

Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!
Have I simplified the problem correctly?
3x^2 + 6x -45 divided by 3x^2 +21x+30 =
I come up with answer of 3(x=5)(x-3) over 3x^2 +21X + 30
Thank you
Your answer is INCORRECT!

You seem to have factored the numerator-expression, but NOT the denominator-expression. 

I'd assume that 3(x = 5)(x - 3) is actually 3(x + 5)(x - 3). In that case, the numerator-expression was correctly factored. 

Now, you just need to factor the denominator and cancel like-factors in the numerator and denominator, as follows: