SOLUTION: tim did 10 lunges on day 1 and continued this doing 4 more lunges on each day.on day 7th he took a break and did nt do any day day.what is the equation for this? express it in the

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Question 1167309: tim did 10 lunges on day 1 and continued this doing 4 more lunges on each day.on day 7th he took a break and did nt do any day day.what is the equation for this? express it in the form y=ax(x+b)+c, where a,b and c are constants.x= no of days and y=no of lunges tim did
Found 3 solutions by mananth, MathTherapy, josgarithmetic:
Answer by mananth(16946) About Me  (Show Source):
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From day 1 to day 6, Tim did 10 lunges on the first day and added 4 more lunges each day. So, on day x
y = 4(x-1) + 10
Simplifying this equation, we get:
y = 4x + 6
day 7, y would be 0.
the equation for the number of lunges Tim did for 7 days will be
y = 4x + 6(x-1)(x<7) + 0 (Day 7 0)
Simplify
y = 4x - 18 (x<7)
y = 4x(x-7) - 18

Answer by MathTherapy(10551) About Me  (Show Source):
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tim did 10 lunges on day 1 and continued this doing 4 more lunges on each day.on day 7th he took a break and did nt do any day day.what is the equation for this? express it in the form y=ax(x+b)+c, where a,b and c are constants.x= no of days and y=no of lunges tim did

I don't believe the x in ax belongs there. So, instead of y = ax(x + b) + c, it should be y = a(x + b) + c

Now, this is an Arithmetic Progression (A.P.) with the following formula: matrix%281%2C3%2C+a%5Bn%5D%2C+%22=%22%2C+a%5B1%5D+%2B+%28n+-+1%29d%29, where:
                                                                          a%5Bn%5D is the value of the nth term                                                                           
                                                                          a%5B1%5D is the 1st term (10, in this case)
                                                                          n is the term number
                                                                          d is he common difference (4, in this case)
                                                             
In the form y = a(x + b) + c, matrix%281%2C3%2C+a%5Bn%5D%2C+%22=%22%2C+4%28n+-+1%29+%2B+10%29 translates to y = 4(x - 1) + 10, with a, b, and c being constants
4, - 1, and 10, respectively. With him taking a break on day 7, he only did lunges for 6 days, so x would range from 1 - 6.

I'm TOTALLY CONFUSED as to what the other person did. His/her equation seems EXTREMELY weird!!!

Answer by josgarithmetic(39616) About Me  (Show Source):
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tim did 10 lunges on day 1 and continued this doing 4 more lunges on each day.on day 7th he took a break and did nt do any day day.what is the equation for this?
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Later parts to that not clear. Only goes for days 1 through 6. 
Domain is integers 1 through 6.

DAY COUNT,x       LUNGES, y
  1                 10
  2                 10+4(2-1)
  3                 10+4(3-1)
  4                 10+4(4-1)
  5                 10+4(5-1)
  6                 10+4(6-1)

highlight%28y=4%28x-1%29%2B10%29