SOLUTION: Determine three consecutive odd integers such that the sum of the smallest and three times the 2nd is 44 more than twice the 3rd. Is the question im asking.
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Question 1165456: Determine three consecutive odd integers such that the sum of the smallest and three times the 2nd is 44 more than twice the 3rd. Is the question im asking.
I get to like but im not sure if that is correct.
n = 1st odd z
n+2 = 2nd odd z
N+3 = 3rd odd z
The correct starting equation is
n + 3*(n+2) = 2*(n+4) + 44.
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Comment from student: Hey! Thanks for your input! I was wondering in the (n+4) part of your answer isn't it n+3 because
I was taught odd is n=3 and even is n+4.
My response. Thanks for asking.
The problem talks about three consecutive odd numbers.
If we denote the first (smallest of them) as "n", then the next odd number is (n+2), and the next after that is (n+4).
