SOLUTION: A chemist wishes to mix a solution that is 10% acid. She has on hand liters of a 6% acid solution and wishes to add some 14% acid solution to obtain the desired 10% acid solution.

Algebra ->  Equations -> SOLUTION: A chemist wishes to mix a solution that is 10% acid. She has on hand liters of a 6% acid solution and wishes to add some 14% acid solution to obtain the desired 10% acid solution.       Log On


   



Question 1164335: A chemist wishes to mix a solution that is 10% acid. She has on hand liters of a 6% acid solution and wishes to add some 14% acid solution to obtain the desired 10% acid solution. she has on hand 6 liters of a 6% acid solution and wishes to add some 14% acid solution to obtain desired 10% acid solution. How much 14% acid solution should she add?
Found 5 solutions by josgarithmetic, greenestamps, MathTherapy, markjames, ikleyn:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
To use y liters of the 14%,
          PERCENT      QTY (Liters)    PURE

           6             6              6*6

          14           y               14y

WANTED    10          y+6             6*6+14y

%286%2A6%2B14y%29%2F%28y%2B6%29=10--------solve for y.
-
14y%2B36=10y%2B60
4y=60-36
y=15-9
highlight%28highlight_green%28y=6%29%29

Answer by greenestamps(13198) About Me  (Show Source):
You can put this solution on YOUR website!


Common sense says that, since 10% is halfway between 6% and 14%, the two ingredients must be mixed in equal amounts.

ANSWER: 6L of the 14% acid.


Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!

S/B: A chemist wishes to mix a solution that is 10% acid. She has on hand 6 liters of a 6% acid solution and wishes to add some 14% acid solution to obtain desired 10% acid solution. How much 14% acid solution should she add?
The 6% solution will increase to 10%, an increase of 4%.
The 14% will be reduced to 10%, a reduction of 4%.
Therefore, the same amount of 6% and 14% solutions need to be mixed.
So, 6 liters of each is needed.
OR
Let amount of 14% solution to mix, be F
Then we get: .06(6) + .14F = .1(6 + F)
.36 + .14F = .6 + .1F
.14F - .1F = .6 - .36
.04F = .24
Amount of 14% solution to mix, or highlight_green%28matrix%281%2C6%2C+F%2C+%22=%22%2C+.24%2F.04%2C+%22=%22%2C+6%2C+L%29%29

Answer by markjames(1) About Me  (Show Source):
You can put this solution on YOUR website!
7.5 litters of 14% acid solution.

Answer by ikleyn(52778) About Me  (Show Source):
You can put this solution on YOUR website!
.

The person with nick-name  @markjames came with the absurdist answer  "7.5 litters"  without any explanations.


Simply ignore it as if   it  NEVER  was here   and as if   you  NEWER  SAW  it.