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Any one of 26 letters of the English alphabet is in the first position;
any one of 26 letters of the English alphabet is in the second position;
any one of 10 digits is in the third position, and
any one of 10 digits is in the fourth position.
All these choices are independent, giving 26*26*10*10 = 67600 different possible IDs. ANSWER
Solved.
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To see many other similar Combinatorics problems, look into the lesson
- Fundamental counting principle problems
in this site.
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lesson is the part of this online textbook under the topic "Combinatorics: Combinations and permutations".
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Free of charge online textbook in ALGEBRA-II
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