SOLUTION: A man rode a bicycle for 12 miles and then hiked an additional 8 miles. The total time for the trip was 5 hours. If his rate when he was riding a bicycle was 10 miles per hour fast

Algebra ->  Equations -> SOLUTION: A man rode a bicycle for 12 miles and then hiked an additional 8 miles. The total time for the trip was 5 hours. If his rate when he was riding a bicycle was 10 miles per hour fast      Log On


   



Question 1162610: A man rode a bicycle for 12 miles and then hiked an additional 8 miles. The total time for the trip was 5 hours. If his rate when he was riding a bicycle was 10 miles per hour faster than his rate walking, what was each rate?
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
                 SPEED           TIME            DIST.
RODE             r+10            12/(r+10)       12
WALK             r               8/r              8
Total                             5

You know what to do,...

Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
.

If you read the problem attentively and then think 30 seconds after reading, you may GUESS the solution MENTALLY:


    12 mph cycling and 2 mph hiking.      ANSWER


If you still prefer algebra solution, then write this "time" equation


    12%2F%28x%2B10%29 + 8%2Fx = 5  hours,


where x is the rate hiking.


To solve this equation, multiply both sides by x*(x+10) and then reduce this equation to the standard quadratic equation form.


Then solve EITHER via quadratic formula OR factoring.


CHECK.  12%2F12 + 8%2F2 = 1 + 4 = 5 hours.

Solved.

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Using  "time"  equation is a  STANDARD  method of solving such problems.
From this lesson,  learn on how to write,  how to use and how to solve a  "time"  equation.

To see many other similar solved problems,  look into the lessons
    - Had a car move faster it would arrive sooner
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    - Time equation: HOW TO use, HOW TO write and HOW TO solve it
in this site.