SOLUTION: If the equation √(2x^2 )-√3x+k=0 with k a constant has two solutions sin θ and cos θ (0 ≤ θ ≤ π/2 ) then k = ?

Algebra ->  Equations -> SOLUTION: If the equation √(2x^2 )-√3x+k=0 with k a constant has two solutions sin θ and cos θ (0 ≤ θ ≤ π/2 ) then k = ?      Log On


   

Question 1161924: If the equation √(2x^2 )-√3x+k=0 with k a constant has two solutions sin θ and cos θ (0 ≤ θ ≤ π/2 ) then k = ?
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Your equation, as written, does not have two solutions. It is a linear equation with one solution, namely .

That is because √(2x^2) means which is equal to making your equation:



So if you meant for your equation to actually be quadratic, then the first term has to be √2(x^2) which means

Repost your question and tell us what you really mean


John

My calculator said it, I believe it, that settles it