SOLUTION: Solve by elimination method. Jill is 27.5 kilometers away from Joe. Both begin to walk toward each other at the same time. Jill walks at 3 kilometers per hour. They meet in 5 ho

Algebra ->  Equations -> SOLUTION: Solve by elimination method. Jill is 27.5 kilometers away from Joe. Both begin to walk toward each other at the same time. Jill walks at 3 kilometers per hour. They meet in 5 ho      Log On


   

Question 1161271: Solve by elimination method.
Jill is 27.5 kilometers away from Joe. Both begin to walk toward each other at the same time. Jill walks at 3 kilometers per hour. They meet in 5 hours. How fast is Joe walking?
Found 3 solutions by ankor@dixie-net.com, MathTherapy, ikleyn:
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Jill is 27.5 kilometers away from Joe.
Both begin to walk toward each other at the same time.
Jill walks at 3 kilometers per hour.
They meet in 5 hours.
How fast is Joe walking?
:
let j = Joe's walking speed
:
Why would you use elimination, there is only one unknown?
Toward each other, their speed are added
write a dist equation, dist = time * speed
5(j + 3) = 27.5
5j + 15 = 27.5
5j = 27.5 - 15
5j = 12.5
j = 12.5/5
j = 2.5 km/hr is Joe's speed

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Solve by elimination method.
Jill is 27.5 kilometers away from Joe. Both begin to walk toward each other at the same time. Jill walks at 3 kilometers per hour. They meet in 5 hours. How fast is Joe walking?
Let Joe's speed be S

Then we get: 5S + 5(3) = 27.5

5S + 15 = 27.5

5S = 12.5

Joe's speed or

Answer by ikleyn(52778) About Me  (Show Source):
You can put this solution on YOUR website!
.

The instruction in the post  "Solve by elimination method"  is  IRRELEVANT  to the problem.


I am 129% sure,  that this instruction came by mistake from another problem.