SOLUTION: How do you express (x^2-3)^3-(2-2x^2)^2+3 (x^2-3) in the form (x^4+Ax^2+B)(x^2+C) where A, B and C are integers?

Algebra ->  Equations -> SOLUTION: How do you express (x^2-3)^3-(2-2x^2)^2+3 (x^2-3) in the form (x^4+Ax^2+B)(x^2+C) where A, B and C are integers?      Log On


   

Question 1157612: How do you express (x^2-3)^3-(2-2x^2)^2+3 (x^2-3) in the form (x^4+Ax^2+B)(x^2+C)
where A, B and C are integers?
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
How do you express (x^2-3)^3-(2-2x^2)^2+3 (x^2-3)
in the form
(x^4+Ax^2+B)(x^2+C) where A, B and C are integers?


After multiplying both sides out,

x%5E6-13x%5E4%2B38x%5E2-40=x%5E6%2B%28A%2BC%29x%5E4%2B%28AC%2BB%29%2BBC

and equating coefficients, we get this system of equations.

system%28A%2BC=13%2CAC%2BB=38%2CBC=-40%29

But that system does not have integer solutions. 

So your problem is impossible. Did you copy something wrong?

Edwin