SOLUTION: (x+y)^2-(x+y)^2=64. Given that x and y are positive integers, which of the following cannot be the value of x+y? A.8 B.10 C.17 D.24

Algebra ->  Equations -> SOLUTION: (x+y)^2-(x+y)^2=64. Given that x and y are positive integers, which of the following cannot be the value of x+y? A.8 B.10 C.17 D.24       Log On


   



Question 1156649: (x+y)^2-(x+y)^2=64. Given that x and y are positive integers, which of the following cannot be the value of x+y?
A.8 B.10 C.17 D.24

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
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(x+y)^2-(x+y)^2=64. Given that x and y are positive integers, which of the following cannot be the value of x+y?
A.8 B.10 C.17 D.24
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Answering formally, NO ONE of the values from the list is valid.


The GLOBAL reason  is that the formula written in the post is  INCORRECT // absurdist.

In the formula,  its left side is  IDENTICALLY  equal to  0  (zero,  ZERO),
while the right side has a constant non-zero value.

Try again,  and be  MORE  ATTENTIVE  next time . . .