SOLUTION: Write the expression as one logarithm.
2 log y^7/x − 5 log y + 1/2 log(x^4y^2)
I got log (y^14/x^7)/(y^5x^2y) which is wrong.
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-> SOLUTION: Write the expression as one logarithm.
2 log y^7/x − 5 log y + 1/2 log(x^4y^2)
I got log (y^14/x^7)/(y^5x^2y) which is wrong.
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Question 1156559: Write the expression as one logarithm.
2 log y^7/x − 5 log y + 1/2 log(x^4y^2)
I got log (y^14/x^7)/(y^5x^2y) which is wrong. Found 3 solutions by MathLover1, greenestamps, MathTherapy:Answer by MathLover1(20849) (Show Source):
If you post a problem and show a wrong answer you got, without showing us how you got it, then we can't help you understand what you did wrong and WHY your answer was wrong.
That means the only way we can help you with the problem is by showing you how WE would work it. You don't learn nearly as much by seeing how we work the problem as you would if we could show you the mistake(s) you made in trying the problem yourself.
If you post questions like this in the future, where you want to know why your answer is wrong, SHOW how you got it....
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The 2 in front is an exponent; this becomes
Again the 5 is an exponent; this becomes
Once more the (1/2) is an exponent; this becomes
In the given expression, the 5 log y is subtracted, indicating division; the 1/2 log(x^4y^2) is added, indicating multiplication.
You can put this solution on YOUR website! Write the expression as one logarithm.
2 log y^7/x − 5 log y + 1/2 log(x^4y^2)
I got log (y^14/x^7)/(y^5x^2y) which is wrong.
Don't know how you got that! Correct simplification follows:
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