SOLUTION: Change to logarithmic form. 3^x = 2 − t I got log(base 3)2-t=x which is wrong. what did i do wrong?

Algebra ->  Equations -> SOLUTION: Change to logarithmic form. 3^x = 2 − t I got log(base 3)2-t=x which is wrong. what did i do wrong?      Log On


   

Question 1156556: Change to logarithmic form.
3^x = 2 − t
I got log(base 3)2-t=x which is wrong. what did i do wrong?
Answer by ikleyn(52777) About Me  (Show Source):
You can put this solution on YOUR website!
.

Take logarithm base 3 of both sides.  You will get


    x = log%283%2C+%282-t%29%29,


valid at t < 2.

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On logarithms and their properties,  see these introductory lessons
    - WHAT IS the logarithm
    - Properties of the logarithm
    - Change of Base Formula for logarithms
    - Evaluate logarithms without using a calculator
    - Simplifying expressions with logarithms
    - Solving logarithmic equations
in this site.

Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Logarithms".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.