SOLUTION: I have 32 fluid ounces of a 3% solution and 32 fluid ounces of a 35% solution. How many ounces of each will I have to add together to make 32 fluid ounces of a 4% solution?
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-> SOLUTION: I have 32 fluid ounces of a 3% solution and 32 fluid ounces of a 35% solution. How many ounces of each will I have to add together to make 32 fluid ounces of a 4% solution?
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Question 1153594: I have 32 fluid ounces of a 3% solution and 32 fluid ounces of a 35% solution. How many ounces of each will I have to add together to make 32 fluid ounces of a 4% solution? Found 2 solutions by josgarithmetic, greenestamps:Answer by josgarithmetic(39616) (Show Source):
---------------------OR MUCH QUICKER---------------------------------------------
-------------meaning 1 fluid ounce of the 35%, and 31 fluid ounce of the 4%.
The other tutor showed how to set up the problem for solving using the standard algebraic method. If an algebraic method is not required, here is a solution by a method that will get you to the answer much faster, and with far less work.
Think of starting with 3% solution and adding 35% solution, stopping when you get to 4%.
To model that, think of "walking" along a number line, starting at 3 and heading towards 35, stopping when you get to 4. From 3 to 4 is 1/32 of the distance from 3 to 35.
That means 1/32 of the mixture needs to be the 35% solution you are adding.
Since you want 32 fl oz of the mixture, that means you need to use 1 fl o of the 35% solution and 31 fl oz of the 3% solution.
Without all the words of explanation, here are the simple calculations required to solve the problem.
4-3=1; 35-3=32 --> 1/32
(1/32) of 32 fl oz = 1 fl oz = amount of 35% solution to use