SOLUTION: Solve the equation, leaving your answer in logarithm 3[2^(2x+2)]-5[2^(x+2)].

Algebra ->  Equations -> SOLUTION: Solve the equation, leaving your answer in logarithm 3[2^(2x+2)]-5[2^(x+2)].      Log On


   

Question 1152876: Solve the equation, leaving your answer in logarithm
3[2^(2x+2)]-5[2^(x+2)].
Found 3 solutions by MathLover1, ikleyn, Alan3354:
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

Solve the equation:
3%282%5E%282x%2B2%29%29-5%282%5E%28x%2B2%29%29=0.............since 2%5E%282x%2B2%29=2%5Ex%2A2%5E%28x%2B2%29, we have
3%282%5Ex%2A2%5E%28x%2B2%29%29-5%282%5E%28x%2B2%29%29=0.....both sides divide by 2%5E%28x%2B2%29
3%282%5Ex%29-5=0
3%282%5Ex%29=5
2%5Ex=5%2F3
log%282%5Ex%29=log%285%2F3%29
x%2Alog%282%29=log%285%29-log%283%29
x=%28log%285%29-log%283%29%29%2Flog%282%29


Answer by ikleyn(52778) About Me  (Show Source):
You can put this solution on YOUR website!
.
Solve the equation, leaving your answer in logarithm
3[2^(2x+2)]-5[2^(x+2)].
~~~~~~~~~~~~~~~~~


There is no ANY equation in this post.



Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Solve the equation, leaving your answer in logarithm
3[2^(2x+2)]-5[2^(x+2)].
================
Equations have = (equal signs).