SOLUTION: One canned juice drink is 30​% orange​ juice; another is 5​% orange juice. How many liters of each should be mixed together in order to get 25 L that is 29​% orange​ juic

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Question 1152758: One canned juice drink is 30​% orange​ juice; another is 5​% orange juice. How many liters of each should be mixed together in order to get 25 L that is 29​% orange​ juice?
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
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One canned juice drink is 30​% orange​ juice; another is 5​% orange juice. How many liters of each should be mixed together in order to get 25 L that is 29​% orange​ juice?
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y, the volume of the 30% orange
25-y, volume of the 5% orange

30y%2B5%2825-y%29=29%2A25

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30y-5y%2B5%2A25=29%2A25
%2830-5%29y=29%2A25-5%2A25
y=%2829%2A25-5%2A25%29%2F%2830-5%29
highlight_green%28y=25%28%2829-5%29%2F%2830-5%29%29%29

highlight%28y=24%29----------liters of the 30% orange juice
highlight%281%29-------------liter of the 5% orange juice
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Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

One canned juice drink is 30​% orange​ juice; another is 5​% orange juice. How many liters of each should be mixed together in order to get 25 L that is 29​% orange​ juice?
Let amount of 30% OJ to mix be T
Then amount of 5% OJ to mix = 25 - T
We then get: .3T + .05(25 - T) = .29(25)
.3T + .05(25) - .05T = .29(25)
.3T - .05T = .29(25) - (.05(25)
.25T = .24(25)
T, or amount of 30% OJ to mix = highlight_green%28matrix%281%2C4%2C+.24%2825%29%2F.25%2C+%22=%22%2C+24%2C+L%29%29
Amount of 5% OJ to mix = highlight_green%28matrix%281%2C4%2C+25+-+24%2C+%22=%22%2C+1%2C+L%29%29