SOLUTION: Warren went on a bike ride of 60 miles. He realized that if he had gone 25 mph faster, he would have arrived 10 hours sooner. How fast did he actually ride?

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Question 1150586: Warren went on a bike ride of 60 miles. He realized that if he had gone 25 mph faster, he would have arrived 10 hours sooner. How fast did he actually ride?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
               SPEED       TIME       DISTANCE

Actual          r          60/r         60

IF            r+25         60/(r+25)    60

Difference                 10

Solve for r in 60%2Fr-60%2F%28r%2B25%29=10.

Simplified, same as 6%2Fr-6%2F%28r%2B25%29=1.

Work through the algebra should show a step, r%5E2%2B25r-150=0;
discriminant is 35%5E2;

r=%28-25%2B35%29%2F2

highlight%28r=5%29