SOLUTION: The position of a body at time 𝑡 seconds is 𝑠(𝑡) = 𝑡^3 − 9𝑡^2 + 14𝑡 meters. Find the body’s velocity each time the acceleration is zero.
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-> SOLUTION: The position of a body at time 𝑡 seconds is 𝑠(𝑡) = 𝑡^3 − 9𝑡^2 + 14𝑡 meters. Find the body’s velocity each time the acceleration is zero.
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Question 1148798: The position of a body at time 𝑡 seconds is 𝑠(𝑡) = 𝑡^3 − 9𝑡^2 + 14𝑡 meters. Find the body’s velocity each time the acceleration is zero. Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! The position of a body at time 𝑡 seconds is 𝑠(𝑡) = 𝑡^3 − 9𝑡^2 + 14𝑡 meters. Find the body’s velocity each time the acceleration is zero.
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V is the 1st derivative of position.
s'(t) = 3t^2 - 18t + 14
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Acceleration is the 2nd derivative of position.
s"(t) = 6t - 18
6t - 18 = 0
t = 3
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Sub 3 for t in the 1st derivative.
