SOLUTION: A particle moves along a horizontal coordinate line so that its position at time 𝑡 is given by 𝑥(𝑡) = 2𝑡^2 − 12𝑡. For what value(s) of 𝑡 is the particle at rest
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-> SOLUTION: A particle moves along a horizontal coordinate line so that its position at time 𝑡 is given by 𝑥(𝑡) = 2𝑡^2 − 12𝑡. For what value(s) of 𝑡 is the particle at rest
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Question 1147471: A particle moves along a horizontal coordinate line so that its position at time 𝑡 is given by 𝑥(𝑡) = 2𝑡^2 − 12𝑡. For what value(s) of 𝑡 is the particle at rest? Answer by ikleyn(52776) (Show Source):
Find the velocity (the speed) as the derivative of the position function over time
v(t) = = 4t - 12.
Equate it to zero and find the time moment when the speed is zero :
4t - 12 = 0,
which gives you the answer for unknown time
t = = 3 units of time. ANSWER
