SOLUTION: Two particles move along a coordinate line. At the end of t seconds their directed distances from the origin, in feet, are given by 𝑠˅1 = 4𝑡 − 3𝑡^2
and 𝑠˅2 = 𝑡^
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-> SOLUTION: Two particles move along a coordinate line. At the end of t seconds their directed distances from the origin, in feet, are given by 𝑠˅1 = 4𝑡 − 3𝑡^2
and 𝑠˅2 = 𝑡^
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Question 1147470: Two particles move along a coordinate line. At the end of t seconds their directed distances from the origin, in feet, are given by 𝑠˅1 = 4𝑡 − 3𝑡^2
and 𝑠˅2 = 𝑡^2 − 2𝑡. When do they have the same velocity? Answer by ikleyn(52778) (Show Source):
Velocity is the first derivative of the coordinate function over time.
For the first particle, velocity is = 4 - 6t.
For the second particle, velocity is = 2t - 2.
Two particles have the same velocity when = , or
4 - 6t = 2t - 2.
From this equation find "t".
It will be your answer.
