SOLUTION: find an equation of the line through the given pair of points (-2,-6) and (-9,-3)

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Question 1144486: find an equation of the line through the given pair of points (-2,-6) and (-9,-3)
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.

First, calculate the slope.


    The formula for the slope of a straight line passing through two given points (x%5B1%5D,y%5B1%5D)  and  (x%5B2%5D,y%5B2%5D)  is
        m = %28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29.

    Substitute the given data  x%5B1%5D = -2,  y%5B1%5D = -5,  x%5B2%5D = -9, y%5B2%5D = -3  into the basic formula

        m = %28-3-%28-6%29%29%2F%28-9-%28-2%29%29 = 3%2F%28-7%29 = -3%2F7.


Next, find an equation of the line having the slope  -3%2F7  and passing through the given point (-2,-6).


    An equation of a straight line in a coordinate plane which has the slope m and passes through the given point  P = (a,b)  is 

        y - b = m*(x-a).     

    Substitute here  m = -3%2F7,  a = -2,  b = -6,  and you will get

        y - (-6) = %28-3%2F7%29%2A%28x-%28-2%29%29,  or equivalently

        y + 6    = %28-3%2F7%29%2A%28x%2B2%29.

    It is the equation in the slope-point form.


    Having this equation, you may transform it to any other equivalent form.

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See the lesson
    - Equation for a straight line in a coordinate plane passing through two given points
in this site.