SOLUTION: show that for any integers x and y :2xy<= x^2 +y^2

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Question 1144142: show that for any integers x and y :2xy<= x^2 +y^2

Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
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show that for any integers x and y : 2xy <= x^2 +y^2
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Start from the inequality


    %28x-y%29%5E2 >= 0,


which is valid for all real numbers "x" and "y".


It is equivalent to


    x%5E2+-+2xy+%2B+y%5E2 >= 0.


Add  2xy to both sides.  You will get an equivalent inequality


    x%5E2+%2B+y%5E2 >= 2xy.


It is EXACTLY what has to be proved.


Solved and completed.


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It is one of the classic and basic inequalities in  Elementary  Math,  but the problem's formulation is  NOT  ADEQUATE.

The adequate formulation is  THIS :

    show that for any real numbers x and y   2xy <= x^2 +y^2.

with replacing   "any integers x and y"   by   "any real numbers x and y".


Actually,  this replacement is  VERY  important and shows that the person who invented/created the original post,
is  UNPROFESSIONAL  in  Math.