Question 1142990: A total of 1740000 is budgeted for roadway. The rule of thumb for this type of project is that the pavement cost twice amount of the base material and the sidewalk cost one-fourth the amount of pavement. Using these figure, how much should the sidewalk cost
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! the total budgeted is 1,740,000
P = pavement
B = base material
S = sidewalk
pavement costs twice the amount of the base material, therefore:
P = 2B
sidewalk costs one fourth the mount of the pavement, therefore:
S = P/4
since P = 2B, and since S = P/4, then S = 2B/4 = B/2
you have:
P = 2B and S = B/2
you also have P + B + S = 1,740,000
replace P with 2B and S with B/2 and you get:
2B + B + B/2 = 1,740,000
multiply both sides of this equation by 2 to get:
4B + 2B + B = 1,740,000
combine like terms to get:
7B = 1,740,000*2 = 3,480,000
solve for B to get B = 3,480,000/7 = 497,142.8571.
P = 2B = 2*497,142.8571 = 994,285.7143.
S = B/2 = 497,142.8571/2 = 248,571.4286.
P + B + S = 1,740,000
the sidewalk should cost 248,571.4286.
that's your solution as best i can determine.
round to the nearest penny, it becomes 248,571.43.
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