SOLUTION: Find an equation for the line parallel to
4y+8x=28
and goes through the point
(−6,−3).
Write your answer in the form
y=mx+b.
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-> SOLUTION: Find an equation for the line parallel to
4y+8x=28
and goes through the point
(−6,−3).
Write your answer in the form
y=mx+b.
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Divide both sides by
This is in the form
where = slope, so
Any line parallel to this line will also
have slope =
So now I have: where = y-intercept
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The unknown line must go through point (-6,-3),
so I can say:
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check:
Does the line go through (-6,-3) ?
OK
Any line parallel to the given line
4y + 8x = 28 (1)
has an equation
4y + 8x = c (2)
with the same left side as the given line (1) has and some constant term "c" in the right side.
The constant term value "c" in (2) is determined from the condition that the point (-6,-3) lies on this line (2).
For it, substitute the coordinates x= -6, y= -3 into equation (2) and determine "c".
4*(-3) + 8*(-6) = c
-12 - 48 = c
-60 = c.
Thus you just determined c = -60, and your equation is
4y + 8x = -60.
You can simplify it by dividing both sides by 4
y + 2x = - 15,
or, to get the requested form,
y = -2x - 15.
It is your final answer.