SOLUTION: Point is the point (2,5) and Q is (6,0).
A line L is drawn through P perpendicular to PQ to meet the y-axis at point R.
1) Find the equation of line L
2) Find the coordinates of
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-> SOLUTION: Point is the point (2,5) and Q is (6,0).
A line L is drawn through P perpendicular to PQ to meet the y-axis at point R.
1) Find the equation of line L
2) Find the coordinates of
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Question 1141045: Point is the point (2,5) and Q is (6,0).
A line L is drawn through P perpendicular to PQ to meet the y-axis at point R.
1) Find the equation of line L
2) Find the coordinates of point R
3) Find the area of triangle OPR Answer by greenestamps(13200) (Show Source):
The slope of the line through P and Q is -5/4; the slope of a line perpendicular to that line is 4/5. Given a perpendicular through P, you have a point and a slope which you can use with either the slope-intercept or point-slope form of a linear equation to find the equation of line L.
2) coordinates of point R (x-intercept of line L)
In the equation from part 1, set y=0 and solve for x.
3) area of triangle QPR (not OPR)
The base is QR; since QR is on the x-axis, the height of the triangle is the y coordinate of P. Use area = one-half base times height.
