Question 1138896: algebraic word pain in the ass problems:
Cookies are set out on a tray for 6 people to take home. one-third, one-fourth, one-eighth, and one-fifth are given to 4 people. The fifth person eats 10 cookies on the spot, with 1 remaining for the 6th person. Find the original number of cookies on the tray.
Answer by greenestamps(13200)   (Show Source):
You can put this solution on YOUR website!
If x is the number of cookies, then the number of cookies the first four people get are (1/3)x, (1/4)x, (1/8)x, and (1/5)x. The last two people get 10 cookies and 1 cookie.
So the total number of cookies, x, is equal to (1/3)x+(1/4)x+(1/8)x+(1/5)x+10+1. That gives a simple equation to solve for x:br>
NB: the LCD for 3, 4, 5, and 8 is 120
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