SOLUTION: algebraic word problems: The width of a rectangle is 3/4 of the length. The perimeter of the rectangle becomes 50 cm when the length and width are each increased by 2 cm. Find

Algebra ->  Equations -> SOLUTION: algebraic word problems: The width of a rectangle is 3/4 of the length. The perimeter of the rectangle becomes 50 cm when the length and width are each increased by 2 cm. Find      Log On


   



Question 1138794: algebraic word problems:
The width of a rectangle is 3/4 of the length. The perimeter of the rectangle becomes 50 cm when the length and width are each increased by 2 cm. Find the length and the width.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = the length in cm
+%283%2F4%29%2Ax+ = the width in cm
Use formula for perimeter
+2%2A%28+x+%2B+2+%29+%2B+2%2A%28+%283%2F4%29%2Ax+%2B+2+%29+=+50+
+2x+%2B+4+%2B+%283%2F2%29%2Ax+%2B+4+=+50+
+%28+7%2F2+%29%2Ax+=+42+
+7x+=+84+
+x+=+12+
and
+%283%2F4%29%2A12+=+9+
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Length = 12 cm
Width = 9 cm
-----------------------
check:
+2%2A%28+12+%2B+2+%29+%2B+2%2A%28+9+%2B+2+%29+=+50+
+28+%2B+22+=+50+
+50+=+50+
OK