SOLUTION: algebraic word problems:
The width of a rectangle is 3/4 of the length. The perimeter of the rectangle becomes 50 cm when the length and width are each increased by 2 cm. Find
Algebra ->
Equations
-> SOLUTION: algebraic word problems:
The width of a rectangle is 3/4 of the length. The perimeter of the rectangle becomes 50 cm when the length and width are each increased by 2 cm. Find
Log On
Question 1138794: algebraic word problems:
The width of a rectangle is 3/4 of the length. The perimeter of the rectangle becomes 50 cm when the length and width are each increased by 2 cm. Find the length and the width.
You can put this solution on YOUR website! Let = the length in cm = the width in cm
Use formula for perimeter
and
-----------------------
Length = 12 cm
Width = 9 cm
-----------------------
check:
OK