Question 1135809: Quadratic Word Problems:
To make a square whose area is a number four times as large as it’s perimeter, how long should each side be?
What I have so far:
X - length of all four sides
Y - area
Z - perimeter
y=4z
4x=z
x^2=y
I’m sorry but this is homework due tomorrow and it is my last question. Can you please help me figure it out?
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617)   (Show Source):
You can put this solution on YOUR website! -----------------------------------------------------------------------
Quadratic Word Problems:
To make a square whose area is a number four times as large as it’s perimeter, how long should each side be?
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x, side length of the square
y, area of the square
 ---------------the "whose..." part of the description
Concentrate on  .
Answer by ikleyn(52778)  (Show Source):
You can put this solution on YOUR website! .
Let X be the square side length, now unknown.
Then the perimeter is P = 4X, while the area is A = X^2.
They want A = 4P, or X^2 = 4*(4X), which is the same as X^2 = 16*X.
Divide by X both sides of the last equation, and you will get
X = 16.
It is your ANSWER : The side length must be 16 units long.
Solved and completed.
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