SOLUTION: solve for x. 6^(3x-4) 2^(2x+3)=648(48)^x

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Question 1134204: solve for x. 6^(3x-4) 2^(2x+3)=648(48)^x
Found 2 solutions by Edwin McCravy, greenestamps:
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
6%5E%283x-4%29%2A2%5E%282x%2B3%29=648%2848%29%5Ex

Take logs of both sides  (can take natural logs instead if preferred)

log%28%286%5E%283x-4%29%2A2%5E%282x%2B3%29%29%29=log%28%28648%2848%29%5Ex%29%29

Use the product-to-sum log fact on both sides:



Use the exponent-to-multiplier log fact on both sides:



Let's break three of those logs down to the side:

     1.  

     2. 

     3.  

Those are all in terms of log(2) and Log(3). 

To keep from getting bogged down with too many complicated symbols,

let A = log(2) and let B = log(3), then

     1.  log%28%286%5E%22%22%29%29=log%28%282%5E%22%22%29%29%2Blog%28%283%5E%22%22%29%29=A%2BB

     2. 

     3. log%28%2848%5E%22%22%29%29=4%2Alog%28%282%5E%22%22%29%29%2Blog%28%283%5E%22%22%29%29=4A%2BB 


Now go back to the equation:



and substitute the expressions in A and B for the logs:

%283x-4%29%28A%2BB%29%2B%282x%2B3%29%28A%29=%283A%2B4B%29%2Bx%2A%284A%2BB%29

Multiply out:

%283Ax%2B3Bx-4A-4B%29%2B%282Ax%2B3A%29=3A%2B4B%2B4Ax%2BBx

3Ax%2B3Bx-4A-4B%2B2Ax%2B3A=3A%2B4B%2B4Ax%2BBx

Combine like terms on the left:

5Ax%2B3Bx-A-4B=3A%2B4B%2B4Ax%2BBx

Get all the terms in x on the left and all the others on the right:

5Ax%2B3Bx-4Ax-Bx=A%2B4B%2B3A%2B4B

Combine like terms:

Ax%2B2Bx=4A%2B8B

Factor out x on the left side and 4 out of the right side:

x%28A%2B2B%29=4%28A%2B2B%29

Divide both sides by (A+2B)

x=4

Edwin

Answer by greenestamps(13198) About Me  (Show Source):
You can put this solution on YOUR website!


The solution using logarithms is valid, but far more work than is needed.

Solve the problem by putting everything in terms of prime factors.

6%5E%283x-4%29%2A2%5E%282x%2B3%29+=+648%2848%5Ex%29


2%5E%285x-1%29%2A3%5E%283x-4%29+=+2%5E%284x%2B3%29%2A3%5E%28x%2B4%29

Equate the exponents of each prime factor:

5x-1+=+4x%2B3 --> x = 4

and

3x-4+=+x%2B4 --> x = 4