SOLUTION: find an equation of the line having the given slope and containing the given point m=0, (0,-1) I know you plug it into y-y1=m(x-x1) but I keep getting a wrong answer help tha

Algebra ->  Equations -> SOLUTION: find an equation of the line having the given slope and containing the given point m=0, (0,-1) I know you plug it into y-y1=m(x-x1) but I keep getting a wrong answer help tha      Log On


   



Question 1133902: find an equation of the line having the given slope and containing the given point m=0, (0,-1)
I know you plug it into y-y1=m(x-x1) but I keep getting a wrong answer
help thank you

Found 3 solutions by josgarithmetic, MathLover1, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
y=-1

-

Knowing the given slope and point, you should not need to "plug it into". If you actually DO plug in what's given using the point-slope form as you wanted, you should still have no trouble. TRY IT! y-%28-1%29=0%28x-0%29.

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

given:
+m=0 -> A horizontal line has a slope of zero.
equation is: y=a
if passes through (0,-1) , => a=-1
so, your line is y=-1
or, you can do it as you already started:



y-y%5B1%5D=m%28x-x%5B1%5D%29.........plug in given data:=>m=0,x%5B1%5D=0 and y%5B1%5D=-1
y-%28-1%29=0%28x-0%29
y%2B1=0
y=-1-> horizontal line





Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!

find an equation of the line having the given slope and containing the given point m=0, (0,-1)
I know you plug it into y-y1=m(x-x1) but I keep getting a wrong answer
help thank you
A 0 (ZERO) slope indicates a HORIZONTAL LINE that's parallel to the x-axis. With a point on the line being (0, - 1).
That HORIZONTAL LINE is the equation: highlight_green%28matrix%281%2C3%2C+y%2C+%22=%22%2C+-+1%29%29
That's ALL!!
Plugging anything in, in this particular case, makes absolutely no sense unless you wish to create more work for yourself.