SOLUTION: A Year hence a Father will be Five times as Old as his Son. Two years ago , The father was 3 times as old his son will be four years hence. Find their Present age
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Question 1133236: A Year hence a Father will be Five times as Old as his Son. Two years ago , The father was 3 times as old his son will be four years hence. Find their Present age Found 2 solutions by addingup, MathTherapy:Answer by addingup(3677) (Show Source):
You can put this solution on YOUR website! F + 1 = 5S
F = 5S - 1
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F - 2 = 3(S + 4)
F - 2 = 3S + 12
F = 3S + 14
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5S - 1 = 3S + 14
2S = 15
S = 7 1/2 or 7.5
The son is 7 1/2 years old, and the father is:
(5 x 7.5) - 1 = 37.5 - 1 = 36 1/2 years old
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Check
first equality given by the problem:
"A Year hence a Father will be Five times as Old as his Son"
36.5 + 1 = 5(7.5)
37.5 = 37.5 Correct
.
second equality given by the problem:
"Two years ago , The father was 3 times as old his son will be four years hence"
F - 2 = 3(S+4)
36.5 - 2 = 3(7.5 + 4)
34.5 = 3 x 11.5
34.5 = 34.5 Correct
You can put this solution on YOUR website!
A Year hence a Father will be Five times as Old as his Son. Two years ago , The father was 3 times as old his son will be four years hence. Find their Present age
The other person's answer is WRONG, and is NONSENSICAL!
Don't these people know by now that it's ABNORMAL to have an age that is NOT an INTEGER?
Correct answers:
