Question 1127166: If 8 = b^-2, what is the value of b?
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! your equation is 8 = b^-2.
since b^-2 = 1/b^2, this equation becomes 8 = 1/b^2.
multiply both sides of this equation by b^2 and divide both sides of this equation by 8 to get b^2 = 1/8.
take the square root of both sides of this equation to get b = plus or minus sqrt(1/8).
to confirm this solution is correct, replace b with plus or minus sqrt(1/8) and solve the equation.
put in your calculator (sqrt(1/8)^-2 and the calculator will tell you that the answer is 8.
put in your calculator (-sqrt(1/8)^-2 and the calculator will tell you that the answer is 8.
this confirms the solution is correct.
the solution is b = plus or minus sqrt(1/8).
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