SOLUTION: a) Find the greatest value of y = - x^2 - 6x + 16
b) Find the least value of the expression above if x lies in the interval -11 < x ≤ 6.
Thank you :)
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-> SOLUTION: a) Find the greatest value of y = - x^2 - 6x + 16
b) Find the least value of the expression above if x lies in the interval -11 < x ≤ 6.
Thank you :)
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Question 1126702: a) Find the greatest value of y = - x^2 - 6x + 16
b) Find the least value of the expression above if x lies in the interval -11 < x ≤ 6.
Thank you :) Found 2 solutions by FrankM, MathTherapy:Answer by FrankM(1040) (Show Source):
You can put this solution on YOUR website! the vertex occurs at X=-b/2a = -(-6)/2(-1) = -3 then solve for Y, 25
(-3,25) is the max
When X=-11, Y= -39
When X= 6, Y= -56 < min for domain -11
You can put this solution on YOUR website!
a) Find the greatest value of y = - x^2 - 6x + 16
b) Find the least value of the expression above if x lies in the interval -11 < x ≤ 6.
Thank you :)
a) The greatest value indicates the y-coordinate of the vertex. This is:
b) For - 11 < x ≤ 6, the LEAST value when x = - 10 is:
For - 11 < x ≤ 6, the LEAST value when x = 6 is:
Therefore, the LEAST value of , if x lies in the interval - 11 < x ≤ 6 is:
