SOLUTION: Two men are racing. J runs a 40 yard dash in 4.39 sec. E runs a 40 yard dash in 6.18 sec. If E is given a 10 yard head start, at what point are the two men tied? I know that s

Algebra ->  Equations -> SOLUTION: Two men are racing. J runs a 40 yard dash in 4.39 sec. E runs a 40 yard dash in 6.18 sec. If E is given a 10 yard head start, at what point are the two men tied? I know that s      Log On


   

Question 1125135: Two men are racing. J runs a 40 yard dash in 4.39 sec. E runs a 40 yard dash in 6.18 sec.
If E is given a 10 yard head start, at what point are the two men tied? I know that speed = distance / time.
J speed = 40 / 4.39.
E speed = 40 / 6.18.
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

Two men are racing.
J runs a 40 yard dash in 4.39 sec . -> speed+s=40yd%2F4.39s -> speed s=9.112%28yd%2Fs%29
E+runs a 40+yard dash in 6.18 sec. -> speed s=40yd%2F6.18s-> speed s=6.473%28yd%2Fs%29
If E is given a 10 yard head start, at what point are the two men tied? (I guess this means when they will meet)
d=s%2At
J runs d=9.112%28yd%2Fs%29%2At
E runs d=10yd%2B6.473%28yd%2Fs%29%2At

when they meet distance will be same, so we have:

9.112%28yd%2Fs%29%2At=10yd%2B6.473%28yd%2Fs%29%2At
9.112%28yd%2Fs%29%2At-6.473%28yd%2Fs%29%2At=10yd
%289.112%28yd%2Fs%29-6.473%28yd%2Fs%29%29t=10yd
2.639%28yd%2Fs%29t=10yd
t=10yd%2F2.639%28yd%2Fs%29
t=10%2F2.639%281%2Fs%29
t=10s%2F2.639
t=3.78931413414172s
t=3.79s

the two men tied: in 3.79s