SOLUTION: A sunflower is planted in a garden and the height of the sunflower increases by 7% per day. 2.59 days after being planted the sunflower is 9.5 inches tall. a. What is the 1-day

Algebra ->  Equations -> SOLUTION: A sunflower is planted in a garden and the height of the sunflower increases by 7% per day. 2.59 days after being planted the sunflower is 9.5 inches tall. a. What is the 1-day      Log On


   



Question 1124417: A sunflower is planted in a garden and the height of the sunflower increases by 7% per day. 2.59 days after being planted the sunflower is 9.5 inches tall.
a. What is the 1-day growth factor for the height of the sunflower?
b. How tall is the sunflower 3.59 days after being planted?
c. How tall is the sunflower 4.59 days after being planted?
d. What is the 2-day growth factor for the height of the sunflower?

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+H%28t%29+=+H%5B0%5D%2A%28+1+%2B+.07+%29%5Et+
Where +t+ is the time in days
+H%5B0%5D+ is the height when planted
+t+=+2.59+ days
+H%282.59%29+=+9.5+ in
————————-
+9.5+=+H%5B0%5D%2A1.07%5E2.59+
+9.5+=+H%5B0%5D%2A1.1915+
+H%5B0%5D+=+7.973+
So, the equation is:
+H%28t%29+=+7.973%2A1.07%5Et+
—————————————-
a)
+t+=+1+
+H%5B1%5D+=+7.973%2A1.07+
+H%5B1%5D+=+8.531+
+1.07+ is growth factor
—————————————-
b)
+t+=+3.59+
+H%283.59%29+=+7.973%2A1.07%5E3.59+
+H%283.59%29+=+7.973%2A1.275+
+H%283.59%29+=+10.166+ in
—————————————-
You can finish