Question 112218This question is from textbook Beginning Algebra
: I could really use help with this word problem:Stan invested $13000, part at 17% and part at 2%. If the total interest at the end of the year is $1,910 how much did he invest at 17%?
This question is from textbook Beginning Algebra
Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website! .17X+.02(13,000-X)=1,910
.17X+260-.02X=1,910
.15X=1,910-260
.15X=1,650
X=1,650/.15
X=11,000 IS THE AMOUNT INVESTED @ 17%.
13,000-11,000=2,000 AMOUNT INVESTED @ 2%.
PROOF
.17*11,000+.02*2,000=1,910
1,870+40=1,910
1,910=1,910
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