SOLUTION: find the equation of the normal to the curve y=x^2-4x at the point where x=-3. find the points A and B where the normal cuts the x-axis and y-axis respectively. Hence find the exac
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-> SOLUTION: find the equation of the normal to the curve y=x^2-4x at the point where x=-3. find the points A and B where the normal cuts the x-axis and y-axis respectively. Hence find the exac
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Question 1122040: find the equation of the normal to the curve y=x^2-4x at the point where x=-3. find the points A and B where the normal cuts the x-axis and y-axis respectively. Hence find the exact length of AB Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! find the equation of the normal to the curve y=x^2-4x at the point where x=-3. find the points A and B where the normal cuts the x-axis and y-axis respectively. Hence find the exact length of AB
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Find the y-value at x = -3
Find the slope at x = -3
The slope of the normal is the negative inverse of the curve's slope.
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Use y-y1 = m*(m-x1) for the equation where (x1,y1) is the point (-3,y)
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