SOLUTION: A piece of wire 48cm long is cut into two pieces. The first is 4x cm long and each piece is bent to form a square. a) Show that A, the sum of the areas of the two squares will be

Algebra ->  Equations -> SOLUTION: A piece of wire 48cm long is cut into two pieces. The first is 4x cm long and each piece is bent to form a square. a) Show that A, the sum of the areas of the two squares will be       Log On


   



Question 1121167: A piece of wire 48cm long is cut into two pieces. The first is 4x cm long and each piece is bent to form a square.
a) Show that A, the sum of the areas of the two squares will be given by A = 2x^2 -24x + 144.
b) At what value of x will the lowest value of A occur?
c) Hence or otherwise, find the lowest value of A.

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Only for getting started,

Pieces of lengths 48-4x, and 4x

Corresponding side lengths of each square 12-x and x
A, sum of their areas, %2812-x%29%5E2%2Bx%5E2=A.
..
.
.