SOLUTION: In this systems of equations, how can I figure out what the 2nd equation's minimum/least dollar value is?
Purchases of $6 or $4 each month. Is there a better way to solve this?
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Purchases of $6 or $4 each month. Is there a better way to solve this?
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Question 1118350: In this systems of equations, how can I figure out what the 2nd equation's minimum/least dollar value is?
Purchases of $6 or $4 each month. Is there a better way to solve this?
Thanks in advance.
m+s=12
6m+4s=?
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In this systems of equations, how can I figure out what the 2nd equation's minimum/least dollar value is?
Purchases of $6 or $4 each month. Is there a better way to solve this?
Thanks in advance.
m+s=12
6m+4s=?
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The second equation is incomplete; it is only an expression, but not an equation. What are the variables, m and s, supposed to be? quantity counts for $6 and $4 ? If they are, then and and each is only whole-numbers or 0.
If vertical axis counts m and horizontal axis counts s then graph for first equation is .
m for vertical axis and s for horizontal axis;
counts y and counts x for m and for x, respectively.
does not establish any constrain unless it is equated to some value.
Are you trying to make something like with as a restriction?
- , but then this is a constant, and .
No minimum for f and no maximum for f.
The SMALLEST value that m can be is 0, and this will make .
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